Q4.

Suppose you are aggregating data and one of your variables has the following properties:

Numerical/continuous data?: Yes

Should be increasing with respect to output?: Yes

Highest value: 23.6

Lowest value: 4.8

Distribution (skewed,normal,uniform etc): normal

Which of the following could be appropriate for transforming the data so that it ranges over the unit interval?

(select all that are reasonable, not just the best one)

Question 4 options:

	Standardize to unit interval. Use x'=0.15(xAM(x))+0.5{"version":"1.1","math":"$x\text{'}=0.15\left({\displaystyle \frac{x-AM\left(\mathit{x}\right)}{}}\right)+0.5$"} ___________________________________
	Standardise so that=0,=1{"version":"1.1","math":"$=0,=1$"}, use x'=xAM(x){"version":"1.1","math":"$x\text{'}=\frac{x-AM\left(\mathit{x}\right)}{}$"} ___________________________________
	Scale to the unit interval. Use x'=x4.823.64.8{"version":"1.1","math":"$x\text{'}=\frac{x-4.8}{23.6-4.8}$"} ___________________________________
	Use a log transformation, x' = ln (x) ___________________________________
	Use a piecewise transformation, x=0.8+0.2x203.6,0.3+0.5x1010,0.3x4.85.2,20 _______________________________________________
	Use a negation, x' = 28.4 - x ___________________________________