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q6 Part A In (Figure 1), consider the closed loop 1-+2 +3 >4->1 This is a cyclic process in which the initial and final states

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q6

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Part A In (Figure 1), consider the closed loop 1-+2 +3 >4->1 This is a cyclic process in which the initial and final states are the same. Use values po = 0.10 atm and Vo = 0.50 L Find the total work done by the system in this process, and show that it is equal to the area enclosed by the loop. Express your answer in joules. VO AEd W Submi Request Answer Part B How is the work done during the process in Part A related to the work done if the loop is traversed in the opposite direction, 1->4 >3->2->1? Express your answer in joules. VO AEd W = Submit Request Answer Figure Part C Complete previous part(s) Part D How much work is done in the cycle 3 >4->2->3? Express your answer in joules. AEd Po 4 3 W -V O Vo Submit Request AnswerPart C Explain why your answer in Part B is different to your answer in Part A. O The negative work done for 1->2 is greater in magnitude than the positive work done in 3->4 and the total work for the cycle has the opposite sign from what it had in Part A. O The negative work done for 2->1 is greater in magnitude than the positive work done in 4-+3 and the total work for the cycle has the opposite sign from what it had in Part A. O The positive work done for 2->1 is greater in magnitude than the negative work done in 4->3 and the total work for the cycle has the opposite sign from what it had in Part A. O The positive work done for 4-+3 is greater in magnitude than the negative work done in 2->1 and the total work for the cycle has the opposite sign from what it had in Part A. Submit Request AnswerFrom the figure we can say that!" W124 20 of : volume i's constants Wy + 3 = Po (8- 2) VO 2 0 6 POVO W3 - 2 = Of " Volume is constants W/21 = 5po ( 2 - 8 ) Vo = - 30 Povo 4 Negative work done is from 251 . So eliminate option ( a ). . eliminate option ( 6 ) 4 magnituge of work in 221 i's greater than in process 4-3 and is negative . So eliminate ophould ] " , Correct option is ( C )

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