QUESTION 1 0m. Use the following data for all questions on this assessment: B=BUUHCUIUHH B H 5 u N 9 m :oo:howuouu-omu m nunmuuuuanoaaaoaoaa IUD-=SH=DHHWWUOHI'H.H uuo Data description D = Unique case identifier Y = Dependent variable: mental health score (01 5 scale) A =X'l: smoking status (0 = Smoker. 1 = Nonsmoker) B = X2: stress score (071 5 scale) Perform an ANCOVA analysis (with interaction) using Y as outcome {dependent variable)r X1 as a categorical predictor and X2 as a numeric predictor. Use 5% as the default level of significance unless specically stated otherwise. Report the Rsquared value from this model (note: this is the proportion of variation in Y that is explained by predictors Xi and X2 in the sample}. O 0.815 O 0.433 6? 0.844 O 1.238 QUESTION 2 002. The pvalue reported for the interaction effect in the ANCOVA ouput is _. (5,) 0.23? O 0.611 O z .001 O 1.238 QUESTION 3 003. The pvalue for interaction effect in the computer output suggests that 0 Since p > 0.05. the interaction ef'ect is signicant. We should ignore the interaction effect and interpret the main effects. (0- Since p > 0.05. the interaction e ect is not signicant. We should ignore the interaction effect and interpret the main effects. 0 Since p > 0.05. the interaction effect is not signicant. We should therefore interpret both the interaction effect and the main effects. 0 Since p > 0.05. the interaction e ect is signicant. We shouldjust interpret the interaction effect and ignore the main effects. QUESTION 4 004. The effect of predictor _ on Y (mental health score] is signicant because the corresponding _ is _than the 5% level of signicance. 0 X1. F value. smaller (0- X2. p value. smaller 0 X1. p value, greater 0 X2. Fvalue. greater QUESTION 5 Q05. The interaction plot for the ANCOVA model [Y = f(X1,X2)] is presented in the figure below. This plot shows that there are more smokers than non -smokers in our sample data. 10 Mental health score 10 15 Stress Score . Y Smoker Non-smoker O True O False