Question 1 (1 point) If a train moves with a velocity of 180 km/h [N] relative to the ground (UrG), and a passenger aboard the train is walking with a velocity of 5 km/h [S] (VPT), the velocity of the passenger relative to the ground ( VPG) is given by: O VPG = UTG - UPG VPG = UPT - VTG VTC = UpT + VPG UPG = VTG + UPT Question 2 (1 point) A cheetah starts from rest and then runs north with a constant acceleration. He travels 220 m in 7.0 s. Calculate his acceleration in m/s^2. 5.8 33 9.0 O 1.1Question 4 (1 point) 6 = 250 The sled in the above image has a mass of 67 kg. There is no friction. What is the Tension in the string? O 240 N O 280 N 590 N 110 N 19Question 3 (1 point) direction of rotation V lettuce A salad spinner with a radius of 18.2 cm rotates clockwise with a frequency of 22.0 Hz. At a given instant, the lettuce in the spinner moves in the westward direction. Determine the magnitude and direction of the centripetal acceleration of the piece of lettuce in the salad spinner at the moment shown above. 2660 m/s^2 [N] 3480 m/s^2 [N] 1 380 000 m/s^2 [N] 13 700 m/s^2 [N]Question 5 (1 point) MA MB Mass A = 1.80 kg, mass B = 1.10 kg. The acceleration of the system is 1.02 m/s^2 [R], what is the coefficient of kinetic friction between mass A and the surface of the table? 0.50 0.34 0.44 0.55