Question 1 (1 point) Use the information in the data table below to calculate the approximate volume of the 111 mmol sample of isopentyl alcohol. solubility M.W. density bp (C) (g/mol) (g/100 (g/mL) mL) Acetic 60.1 118 1.049 miscible acid Isopentyl 88.1 130 0.815 2.7 alcohol Isopentyl 130.2 142 0.876 0.25 acetate Sulfuric 98.1 290 acid 1.84 miscible A) 8,000 mL B) 12,000 mL C) 12 mL D) 8 mL Question 2 (1 point) Why must the alcohol be measured by mass in this experiment but the glacial acetic acid and sulfuric acid can be measured by volume? A) The graduated cylinder is not large enough to measure the volume of the alcohol required, so the mass must be measured B) Glacial acetic acid and sulfuric acid are liquids, so measuring the volume is more convenient. C) It is easier to measure the mass of the alcohol than the volume. D) The alcohol is too volatile to measure the volume. E) The alcohol is the limiting reagent, so the amount must be precise (to 4 decimal places by mass vs 1 decimal place by volume). Question 3 (1 point) What is the purpose of the glacial acetic acid in the reaction? O A) It is the excess reactant OB) It is the limiting reactant OC C) It is the catalyst OD D) It is the drying agent OE) It is the distillation agent Question 5 (1 point) When the isopentyl acetate (IPA) product is washed with water and aqueous sodium bicarbonate, which is the organic layer? A) The bottom layer (aqueous sodium bicarbonate). Water is more dense than the insoluble IPA. B) There is no organic layer. IPA is not organic and neither is aqueous sodium bicarbonate. C) There are no layers. IPA is too soluble in water to form layers. D) The top layer (IPA). IPA is not soluble with water and is less dense than water. E) The bottom layer (IPA). IPA is not soluble with water and is more dense than water