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Question 1 (1 point) What is the surface integral f d.A in m of a sphere of radius (3.47x10*1) cm? Note: Your answer is assumed
Question 1 (1 point) What is the surface integral f d.A in m of a sphere of radius (3.47x10*1) cm? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer Question 2 (1 point) Saved The potential difference between two points is 100 V. These points are separated by 0.5 m. If a particle with a charge of 2 C is moved from one of these points to the other, the magnitude of the work done is: O 2J 100 V 100 J O 50 J O 200 J Question 3 (1 point) How does the addition of a dielectric NOT affect a parallel plate capacitor? It decreases the capacitance of the capacitor It stores energy in the dielectric by polarization It usually increases the dielectric strength and increases the breakdown Voltage O It allows more charge to be held on the plates at a given potential It lowers the overall electric field between the charge platesQuestion 4 (1 point) If the electric potential is constant in a region of space, what can you say about the electric field? It must be the same constant It must be decreasing O It must be zero Question 5 (1 point) Calculate the potential in volts at a distance of (4.520x10*0) m from a point charge of (-6.6x10^0) UC, if the point charge is inside a dielectric material with a dielectric constant k = (1.750x10^0) Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer Question 6 (1 point) Calculate the potential in volts at a distance of (7.3x10*0) um from a point charge of (-5.020x10^0) PC. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer Question 7 (1 point) Charges Q1 =(-7.300x10^0) nC and Q2 =(-1.7x10*0) nC are distances 1 = (2.40x10*0) m and r2 = (2.300x10^0) m from point P respectively. Calculate the potential in volts at point P. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10Question 8 (1 point) Q15 P 12 Q2 Charges Q1 =(-8.090x10^0) nC and Q2 =(-8.1x10^0) nC are distances r1 = (3.00x10^0) m and r2 = (8.300x10^0) m from point P respectively. Calculate the potential in volts at point P, if the charges are in a dielectric material, with a dielectric constant k = (2.28x10^0). Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer Question 9 (1 point) Three identical charges Q = (2.36x10^-9) C lie at corners of a square of side (1.5x10^0) metres. Calculate the potential in volts at the centre of the square. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 AnswerQuestion 10 (1 point) A parallel plate capacitor has a surface charge density of o = (2.0x10^0) uC/m2. Calculate the potential difference between the plates in V, if there is a dielectric material with dielectric constant k = (1.16x10^1) between the plates, which are (7.940x10^0) mm apart. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10
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