Question 1 [1 point} What is the surface integral :fdfl in m2 oFa long thin wire with circular cross section, length {4.72x10m} m and radius {3.01?0x10\"0] mm? Hint: "long thin" means you can neglect the ends of the wire. L Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: Answer Question 2 [1 point} An electrically charged object creates an electric field. The electric potential due to this object: points in the same direction as the field is a non-negative scalar is a vector that makes circular paths around the object is a scalar but will be positive or negative depending on the sign of the charge 00000 is a vector that points towards or away from the object, depending on the sign ofthe charge Question 3 (1 point) A parallel-plate capacitor has a plate area of 0.20 m and a plate separation of 0.10 mm. To obtain an electric field of 2.0 x 10" V/m between the plates, the magnitude of the charge on each plate should be: 1.8 x10-5 c 3.5 X106 C O 7.3 X106 c 1.4 X 10 5 c 8.9 X 10-5C Question 4 (1 point) The total charge stored in a capacitor of a known capacitance depends on: the resistance between the capacitor plates the current through the capacitor the potential difference across the capacitor the type of dielectric used the magnetic field around the capacitorQuestion 5 (1 point) Calculate the potential in volts at a distance of (2.670x10^0) m from a point charge of (-4.29x10^0) pC, if the point charge is inside a dielectric material with a dielectric constant K = (1.9x10^0) Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer Question 6 (1 point) Calculate the potential in volts at a distance of (1.36x10^0) mm from a point charge of (4.6x10^0) HC. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 AnswerQuestion 7 (1 point) P Q2 Charges Q1 =(2.71x10*0) nC and Q2 =(-3.94x10*0) nC are distances r1 = (1.6x10*0) m and r2 - (2.10x10^0) m from point P respectively. Calculate the potential in volts at point P, if the charges are in a dielectric material, with a dielectric constant k " (2.100x10*0). Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 AnswerQuestion 8 (1 point) Q15 1 1 P 12 Q26 Charges Q1 =(7.950x10^0) nc and Q2 =(8.15x10^0) nC are distances r1 = (5.30x10^0) m and r2 = (3.2x10^0) m from point P respectively. Calculate the potential in volts at point P, if the charges are in a dielectric material, with a dielectric constant k = (3.77x10^0). Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer Question 9 (1 point) Four identical charges Q = (4.4x10^-9) C lie at corners of a square of side (4.880x10^0) metres. Calculate the potential in volts at the centre of the square. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 AnswerQuestion 10 (1 point) A parallel plate capacitor has a charge of +(1.00x10^-12) C on the plates, which have an area of (5.9x10^0) cm- . Calculate the magnitude of the electric field between the plates in V/m, if there is a dielectric material with dielectric constant K = (2.590x10^0) between the plates. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10