Question 1 (3 points) ) Listen A university conducted a survey of its recent graduates. The university wanted to measure the quality of a new Engineering course. A survey was conducted during the first offering of the course to evaluate its overall quality. The results of the survey are shown below: Needs Improvement: 55% Meets Expectations: 30% Excellent: 15% The university made improvements to the course earlier this year. Then it conducted another survey to evaluate how these improvements worked. A total of 500 students were surveyed. Their results are shown below: Needs Improvement: 175 students Meets Expectations: 225 students Excellent: 100 students You want to perform a chi-square test for goodness of fit, to see if students' views have changed about the course. Which of the following Python scripts prints the P- value and test statistic for the chi-square test? Select one. from scipy stats import chisquare statistic, pvalue = goodness_of_fit([175,225,100], f_exp=[275,150,75]) print(statistic) print(pvalue) from scipy stats import chisquare statistic, pvalue = goodness_of_fit([275,150,75], f_exp=[175,225,100]) print(statistic) print(pvalue) O from scipy.stats import chisquare statistic, pvalue = chisquare([275,150,75], f_exp=[175,225,100]) print(statistic) print(pvalue) from scipy.stats import chisquare statistic, pvalue = chisquare([175,225,100], f_exp=[275,150,75]) print(statistic) print(pvalue)Question 2 (3 points) Listen A biologist is studying the composition of birds on a lake and counts 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons. From previous studies performed around the same time of the year, she expects 50% of the birds to be ducks, 23% to be geese, 12% to be cranes, 10% to be swans, and 5% to be herons. What are the expected and observed counts? Select one. Expected = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Observed = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Expected = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Observed = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Expected = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Observed = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Expected = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Observed = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Question 3 (3 points) ) Listen Which of the following Python methods is used to perform chi-square goodness of fit tests? Select one. O tukeyhad from scipy.stats submodule Of_oneway from scipy.stats submodule O chisquare from scipy.stats submodule anova_Im from scipy.stats submoduleLJESIIL'II'I il- [a points] mu What is the use of the chi-so uare goodness of fit test?I Select one. 0 To test how close the distribution of a population is to a Stu dent's t-distribution 0 To test the difference in three or more population means 0 To test how close the distrlbution of a population is to an expected distributlon 0 To test how close the distribution of a population is to a Normal distribution Question 5 {3 points] mu A biologist is studying the oom position of birds on a lake and counts 61 Ilzlucltsr 1? geese. 11 cranes1 15 swans. and s herons. From previous studies performed around the same time of the year, she expects 5095 of the birds to be ducks. 2336 to be geese. 12% to be cranes1 l to be swansI and 5% to be herons. What are the correct null and alternative hypotheses for performing a chi-square goodness of fit test? Select one. 0 Hull Hypothesis Ho: The distribution of birds observed follows the Normal distribution. Alternative Hypothesis H1: The distribution of birds observed does not follow the Normal distribution. 0 Hull Hypothesis Ho: The distribution of birds observed does not follow the distribution from previous studies. Alternative Hypothesis H1: The distribution of birds observed follows the distribution from previous studies. 0 Hull Hypothesis H5: The distribution of birds observed follows the distribution from previous studies. Alternative Hypothesis H1: The distribution of birds observed does not follow the distribution from previous studies. 0 Hull Hypothesis Ho: The distribution of birds observed follows the Student's t- distribution. Alternative Hypothesis H1: The distribution of birds observed does not follow the Stu dent's t-distribution