Question 1 (5 points)

Determine whether the outcome is a Type I error, a Type II error, or a correct decision. A test is made of H₀: = 48 versus H₁: 48. The true value of is 48 and H₀ is not rejected.

Question 1 options:

	Type II error
	Correct decision
	Type I error

Question 2 (5 points)

Use technology to find the P-value for the following values of the test , sample , and alternate hypothesis H₁. , ,

Question 2 options:

	0.1150
	0.2300
	0.1157
	0.2314

Question 3 (5 points)

A market research firm reported that the mean annual earnings of all family practitioners in the United States was $179,574. A random sample of 38 family practitioners in New York that month had mean earnings of = $198,513 with a standard deviation of $35,113. You wish to test whether family practitioners in New York make more than the national average. State a conclusion regarding H₀. Use the level of significance.

Question 3 options:

	Reject H0: the mean annual earnings appear to be greater than the national average.
	Do not reject H0: there is insufficient evidence to conclude that the mean annual earnings are greater than the national average.
	There is not enough information to draw a conclusion.

Question 4 (5 points)

Find the critical value for the following values of the significance , sample , and alternate hypothesis H₁. , ,

Question 4 options:

	-1.895
	-2.447
	-1.943
	-1.645

Question 5 (5 points)

In a survey of 597 cigarette smokers, 81 of them reported that they have tried hypnosis therapy to try to quit smoking. Can you conclude that less than one-tenth of smokers have tried hypnosis therapy? Use the level of significance.

Question 5 options:

	Yes
	No conclusion is possible.
	No

Question 6 (5 points)

The following output from MINITAB presents the results of a hypothesis test. Do you reject H₀ at the level?

Question 6 options:

	No
	Yes
	There is not enough information to draw a conclusion.

Question 7 (5 points)

The following display from a TI-84 Plus calculator presents the results of a hypothesis test for a population proportion p. Can H₀ be rejected at the 0.05 level?

Question 7 options:

	No
	Yes

Question 8 (5 points)

The following display from a TI-84 Plus calculator presents the results of a hypothesis test. What is the value of the test statistic?

Question 8 options:

	60
	-2.527972
	57.40
	1.988528

Question 9 (5 points)

The following output from MINITAB presents the results of a hypothesis test for a population mean . Do you reject H₀ at the level of significance?

Question 9 options:

	No
	Yes

Question 10 (5 points)

A sample of 39 students enroll in a program that claims to improve scores on the quantitative reasoning portion of the Graduate Record Examination (GRE). The participants take a mock GRE test before the program begins and again at the end to measure their improvement. The mean number of points improved was . Assume the standard deviation is and let be the population mean number of points improved. To determine whether the program is effective, a test is made of the hypotheses versus . Compute the P-value.

Question 10 options:

	0.0076
	0.0153
	0.0305
	1.8735

Question 11 (5 points)

In a simple random sample of 77 families, the mean number of children is 2.2 with a standard deviation of 0.9. You wish to determine if the population mean differs from 2.1 children per family. Determine the type of parameter to be tested and compute the test statistic.

Question 11 options:

	Test for a standard deviation; test statistic 454.1235
	Test for a proportion; test statistic 2.9250
	z-test for the mean; test statistic 0.9750
	t-test for the mean; test statistic 0.9750

Question 12 (5 points)

A test is made of versus . A sample of size is drawn, and . The population standard deviation is . Compute the value of the test statistic z and determine if H₀ is rejected at the level.

Question 12 options:

	0.22, H0 rejected
	0.22, H0 not rejected
	1.68, H0 rejected
	1.68, H0 not rejected

Question 13 (5 points)

A test has power 0.85 when . True or false: the probability of making a correct decision when is 0.15.

Question 13 options:

	False
	True

Question 14 (5 points)

Mercury is a heavy metal that can cause severe health problems in even small concentrations. Fish and shellfish efficiently concentrate mercury into their flesh, so it is important to monitor seafood for its mercury content. An extensive study conducted in 1980 concluded that the mean mercury level in oysters from the White Bear estuary was 0.021 parts per million (ppm) with a standard deviation ppm. In 2012, a sample of 47 oysters from the same estuary exhibited a mean mercury concentration of . Can you conclude that the 2012 mercury concentration is lower than in 1980? Use the level of significance.

Question 14 options:

	No. There is insufficient evidence to conclude that the mercury concentration has decreased from 1980 to 2012.
	Yes. The mercury concentration appears to be lower in 2012.
	There is not enough information to reach a conclusion.

Question 15 (5 points)

A psychologist is designing an experiment in which rats will navigate a maze. Ten rats run the maze, and the time it takes for each to complete the maze is recorded. The results are as follows: 62.6 60.4 42.8 67.7 63.5

65.9

59.5

65.8

62.4

51.0

Following is a boxplot for the data. Is it reasonable to assume the conditions for performing a hypothesis test are satisfied?

Question 15 options:

	No
	Yes

Question 16 (5 points)

The following display from a TI-84 Plus calculator presents the results of a hypothesis test for a population proportion p. What is the value of the sample proportion ?

Question 16 options:

	0.046479
	90
	0.256
	0.34

Question 17 (5 points)

A random sample of size 12 from a normal distribution has standard deviation . Test . Use the level of significance.

Question 17 options:

	Do not reject H0.
	Reject H0.

Question 18 (5 points)

The following display from a TI-84 Plus calculator presents the results of a hypothesis test for a population mean . How many degrees of freedom are there?

Question 18 options:

	52
	50
	33
	51

Question 19 (5 points)

The following output from MINITAB presents the results of a hypothesis test. What is the P-value?

Question 19 options:

	1.968656
	46.10
	0.014319
	2.449164

Question 20 (5 points)

The Golden Comet is a hybrid chicken that is prized for its high egg production rate and gentle disposition. According to recent studies, the mean rate of egg production for 1-year-old Golden Comets is 5.6 eggs/week. Sarah has 41 1-year-old hens that are fed exclusively on natural scratch feed: insects, seeds, and plants that the hens obtain as they range freely around the farm. Her hens exhibit a mean egg-laying rate of 5.9eggs/day. Sarah wants to determine whether the mean laying rate for her hens is higher than the mean rate for all Golden Comets. Assume the population standard deviation to be eggs/day. Compute the value of the test statistic.

Question 20 options:

	0.18
	0.87
	1.13
	1.47