Question 1 b a A B All pipes steel Schedule 40 Valve LID=240 d The above diagram shows a parallel piping system. Oil with properties as shown in table below flows through the system. The nominal size of each pipe segment (a, b, c & d) is provided in the table below. Fluid pressure at point A and B are 980 kPa and 690 kPaa respectively. The distance between points A and B (the length of the branches) is 40 m. Calculate fluid flowrate and velocity in the main pipe segments (a & c) and fill in the answer table. Ignore the T-junction losses at points A and B. The top leg is the one without the valve. The system is horizontal. Main refers to the pipes containing Points A and B. a (in) = b (in) = c (in) = d (in) = Branch Length (m) = PA (kPaa) = PB (kPaa) = Oil y (kN/m?) = Oil v (m/s) = Elbow LelD= 8 5 8 4 40 980 690 7.9 8.30E-06 30 = Total Actual hl (m) Top fr Top v (m/s) Top Nr Topf Top Q (m/s) Bottom fr Bottom v (m/s) Bottom NR Bottom f Bottom Q (m/s) Main Q (m/s) Main v (m/s)