question 1:

Data 6.0 23 m Mass of Cart = 6.25 0 (75 Distance spring is compressed x= Angle of incline 0 = 1Co Initial position of cart = Trial Max. Value of d h= d sine 1 0. 14 1 m 0. 0 245 2 0. 1 6 2 m C. 0281 3 0. 137 m 0 . 023 7 4 0. 162 m 0. 6 281 5 0. 166 m 0. 0288 Table 2this new adjustable end stop 250 = cant Fig. 1 Data Added Mass Position Displacement X Force (mg) 0. 031 m O M OFISOKS 0. 0 29- m 0.002m 1. 47 6 . 350 1 19 0. 603 m 0.005m 3. 43 0. 550 Kq 0 . 0 22 m 0.0cam 5. 39 G . 75 0 ks 0. 020 m o. ocllm 7.35 Table 1IV. Analysis of Data (1) Using the data in Table 1, plot force versus displacement ( excel and find the slope. The slope is e with this lab. make sure your units are correct) on qual to the effective spring constant, k. Include your graph k: N/m w (3) Calculate the nal gravitational potential energy, when the cart has reached the maximum height. YOU will use the average height calculated from table 2. Show your work in the space below. U: UgfmV / 9 \\I / v