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QUESTION 1 Determine the critical valuez /2 that corresponds to the given level of confidence. 86% 1.080.811.161.48 1 points QUESTION 2 Determine the critical valuez
QUESTION 1
- Determine the critical valuez/2that corresponds to the given level of confidence.
- 86%
- 1.080.811.161.48
1 points
QUESTION 2
- Determine the critical valuez/2that corresponds to the given level of confidence.
- 97%
- 0.832.171.921.88
1 points
QUESTION 3
- Determineandfrom the given parameters of the population and the sample size. Round the answer to the nearest thousandth where appropriate.
- = 38, = 24, n = 16
- = 38, = 6= 38, = 24= 38, = 1.5= 9.5, = 6
1 points
QUESTION 4
- Find the critical value(s).
- Determine the critical value for a right-tailed test of a population standard deviation with 16 degrees of freedom at thelevel of significance.
- 24.99626.2967.96234.267
1 points
QUESTION 5
- Find the critical value.
- Determine the critical value for a right-tailed test of a population mean at the = 0.005 level of significance with 28 degrees of freedom.
- 2.7711.701-2.7632.763
1 points
QUESTION 6
- Find the t-value.
- Find the critical t-value that corresponds to 90% confidence and n = 15.
- 2.1451.7612.6241.345
1 points
QUESTION 7
- Find the t-value.
- Find the t-value such that the area in the right tail is 0.005 with 28 degrees of freedom.
- 2.7632.7711.701-2.763
1 points
QUESTION 8
- Provide an appropriate response. Round the test statistic to the nearest thousandth.
- Compute the standardized test statistic, 2, to test the claim 2= 25.8 if n = 12, s2= 21.6, and
- 0.4929.20912.96118.490
1 points
QUESTION 9
- Provide an appropriate response. Round the test statistic to the nearest thousandth.
- Compute the standardized test statistic, 2, to test the claim 2 16.2 if n = 15, s2= 13.5, and
- 23.8918.71311.66712.823
1 points
QUESTION 10
- Provide an appropriate response.
- A candidate for state representative of a certain state claims to be favored by more than half of the voters. If a hypothesis test is performed, how should you interpret a decision that rejects the null hypothesis?
- There is not sufficient evidence to support the claim p = 0.5.There is sufficient evidence to reject the claim p =0.5.There is not sufficient evidence to reject the claim p = 0.5.There is sufficient evidence to support the claim p = 0.5.
1 points
QUESTION 11
- Provide an appropriate response.
- A local bank needs information concerning the savings account balances of its customers. A random sample of 15 accounts was checked. The mean balance was $686.75 with a standard deviation of $256.20. Find a 98% confidence interval for the true mean. Assume that the account balances are normally distributed. Round to the nearest cent.
- ($238.23, $326.41)($487.31, $563.80)($326.21, $437.90)($513.17, $860.33)
1 points
QUESTION 12
- Provide an appropriate response.
- A researcher at a major clinic wishes to estimate the proportion of the adult population of the United States that has sleep deprivation. What size sample should be obtained in order to be 95% confident that the sample proportion will not differ from the true proportion by more than 5%?
- 10271385769
1 points
QUESTION 13
- Provide an appropriate response.
- A student randomly selects 10 paperbacks at a store. The mean price is $8.75 with a standard deviation of $1.50. Construct a 95% confidence interval for the population standard deviation, . Assume the data are normally distributed.
- ($1.76, $3.10)($0.43, $1.32)($1.03, $2.74)($1.43, $2.70)
1 points
QUESTION 14
- Provide an appropriate response.
- Construct a 95% confidence interval for the population mean, . Assume the population has a normal distribution. A sample of 20 part-time workers had mean annual earnings of $3120 with a standard deviation of $677. Round to the nearest dollar.
- ($2657, $2891)($2803, $3437)($1324, $1567)($2135, $2567)
1 points
QUESTION 15
- Provide an appropriate response.
- Construct a 95% confidence interval for the population standard deviation of a random sample of 15 crates which have a mean weight of 165.2 pounds and a standard deviation of 12.2 pounds. Assume the population is normally distributed.
- (9.4, 17.8)(2.6, 5.5)(8.9, 19.2)(79.8, 370.2)
1 points
QUESTION 16
- Provide an appropriate response.
- Determine the point estimate of the population mean and margin of error for the confidence interval with lower bound 14 and upper bound: 26.
- = 20, E = 12= 14, E = 12= 20, E = 6= 26, E = 6
1 points
QUESTION 17
- Provide an appropriate response.
- Find the critical value for a left-tailed test with = 0.05.
- -1.28-1.645-2.33-1.96
1 points
QUESTION 18
- Provide an appropriate response.
- Find the critical values,and, for 95% confidence and n = 12.
- 3.816 and 21.9202.603 and 19.6754.575 and 26.7573.053 and 24.725
1 points
QUESTION 19
- Provide an appropriate response.
- Find the standardized test statistic t for a sample with n = 12,= 13.2, s = 2.2, and = 0.01 ifRound your answer to three decimal places.
- 2.1321.9911.8902.001
1 points
QUESTION 20
- Provide an appropriate response.
- Find the standardized test statistic t for a sample with n = 10,= 16.2, s = 1.3, andifRound your answer to three decimal places.
- -2.617-2.189-3.010-3.186
1 points
QUESTION 21
- Provide an appropriate response.
- If we do not reject the null hypothesis when the null hypothesis is in error, then we have made a
- Type II errorType errorType I errorCorrect decision
1 points
QUESTION 22
- Provide an appropriate response.
- If we reject the null hypothesis when the null hypothesis is true, then we have made a
- Type errorCorrect decisionType II errorType I error
1 points
QUESTION 23
- Provide an appropriate response.
- In a random sample of 60 dog owners enrolled in obedience training, it was determined that the mean amount of money spent per owner was $109.33 per class. Assuming the population standard deviation of the amount spent per owner is $12, construct and interpret a 95% confidence interval for the mean amount spent per owner for an obedience class.
- ($106.29, $112.37); we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.29 and $112.37.($106.74, $111.92); we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.74 and $111.92.($106.23, $112.43); we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.23 and $112.43.($106.78, $111.88); we are 95% confident that the mean amount spent per dog owner for a single obedience class is between $106.78 and $111.88.
1 points
QUESTION 24
- Provide an appropriate response.
- Suppose a population has a mean of 7 for some characteristic of interest and a standard deviation of 9.6. A sample is drawn from this population of size 64. What is the standard error of the mean?
- 3.30.150.71.2
1 points
QUESTION 25
- Provide an appropriate response.
- The business college wants to determine the proportion of business students who have extended time between classes. If the proportion differs from 30%, then the lab will modify a proposed enlargement of its facilities. Suppose a hypothesis test is conducted and the test statistic is 2.5. Find the P-value for a two-tailed test of hypothesis.
- 0.05
0.10
1 points
QUESTION 26
- Provide an appropriate response.
- The mean age of professors at a university is 53.9 years. If a hypothesis test is performed, how should you interpret a decision that fails to reject the null hypothesis?
- There is sufficient evidence to reject the claim = 53.9.There is not sufficient evidence to reject the claim = 53.9.There is sufficient evidence to support the claim = 53.9.There is not sufficient evidence to support the claim = 53.9.
1 points
QUESTION 27
- The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed and the parameter that is being tested.
- H0: = 9.3
- H1: 9.3
- Two-tailed,Right-tailed, Left-tailed,Two-tailed,
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