Question 1 of 7 (8 points) | Attempt 1 of 1 | View question in a popup | @) 2h 58m Remaining 9.5 Section Exercise 16 Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.75. Assume that in a sample of 45 teenagers, the sample DUo standard deviation of daily TV time is 2.4 hours, and that the population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers differs from 2.75? Use the a = 0.10 level of significance. Part: 0 / 5 Part 1 of 5 State the appropriate null and alternate hypotheses. H:0 = 2.75 H :G 2.75 This hypothesis test is a two-tailed test. Part: 1 / 5 Part 2 of 5 Find the critical values. Round the answer to three decimal places. For a = 0.10, the critical values are |1 | and |2. Part: 2 / 5 Part 3 of 5 Compute the test statistic. Round the answer to three decimal places. x7 = 1 Part: 3 / 5 Part 4 of 5 Determine whether to reject Ho. At the a = 0.10 level, (Choose one) V the null hypothesis Ho. X 5