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Question 1: The range is $ million. (Round to the nearest integer as needed.) The variance is million dollars squared. (Round to the nearest integer

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Question 1:

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The range is $ million. (Round to the nearest integer as needed.) The variance is million dollars squared. (Round to the nearest integer as needed.) The standard deVIation is ll; million. (Round to the nearest integer as needed.) What do the results tell us about the population of all celebrities? O A. Because the statistics are calculated from the data, the measures of variation are typical for all celebrities. O B. Because the data are from celebrities With the highest net werths, the measures of variation are not at all typical for all celebrities. O C. Because the data are from celebrities With the highest net worths, the measures of variation are typical for all celebrities. O D. Because the statistics are calculated from the data, the measures of variation cannot tell us about other celebrities. ANOVA table Source DF SS MS F-Stat P-value Columns 2 1087.8875 543.94375 58.4342 H2 > H3 Hy = H2 = H3 H1 = H2 = H3 At least one of the means is different from the others All of the means are differentAll of the means are different At least one of the means is different from the others Hy = 12 = H3 Hy = H2 = H3 H1 > H2 > H3Listed below are the numbers of words spoken in a day by each member of eight different randomly selected couples. Complete parts (a) and (b) below. Male 15,532 25,485 1380 7912 19,614 15,964 13,717 25,412 Female 24,806 13,928 18,237 18, 147 13,223 16,869 16,609 18,209 a. Use a 0.01 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, uo is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test? Ho- Ha v word(s) H1 : Hd V word(s ) (Type integers or decimals. Do not round.) Identify the test statistic. t= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is the significance level, the null hypothesis. There sufficient evidence to support the claim that males speak fewer words in a day than females. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval is | | word(s)

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