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Question 1: When an ac source with a peak potential difference of 42 V is connected to a series RLC circuit, the peak current is
Question 1:
When an ac source with a peak potential difference of 42 V is connected to a series RLC circuit, the peak current is 5 A. The capacitor is C = 25 /F, the frequency is 150 Hz, and the current leads the potential difference by 55", Find the resitance and the inductance. R = L : HIn an RLC series circuit, the rms potential difference provided by the source is \\ = 200 V, and the frequency is f = _ Hz. Given that _ = 0.5 H, C = 25 /F, and VR,rms = 80 V, find: a) I (rms); I=A bj R. R c) VI (rms); VL d) Ve (rms). Vo VIn an RLC series circuit, the source has a potential difference of 131] V {rms]. The impedance is ll and the resistance is 44 5.1. Find: a] the average power delivered by the source; p 2 E] w lo] the power factor; C] In an RLC series circuit, the source has a peak potential difference of 130 V, and a frequency of 50 Ha. Take R = 140, C = 230 /F, L = 0.8 H. Find: a) Xz and Xc: Xc b) the phase angle; degrees c) the average power delivered by the source; W d) the power factorStep by Step Solution
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