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Question 1 - ( X 2.10 Newton's X s Student Portal X Mail - Carreor X Content X (27) Newton's X + X -> https://prod.reader-ui.prod.mheducation.com/epub/sn_91e0/data-uuid-...
Question 1 - ( X 2.10 Newton's X s Student Portal X Mail - Carreor X Content X (27) Newton's X + X -> https://prod.reader-ui.prod.mheducation.com/epub/sn_91e0/data-uuid-... A ABP . . . 35 of 439 Aa SOLUTION G = 6.67 x 10-11 Nm2/kg2 m1 = 60.0 kg F = Gmim2 d2 m2 = 60.0 kg = (6.67x10- Nm2/kg2)(60.0kg)(60.0kg) d = 1.00 m (1.00m)2 F =? Nm-/kg2 = (6.67 x 10-11)(3.60 x 103) kg2 m- = 2.40 x 10-7 (Nm2) (mz ) = 2.40 x 10-7N (Note: A force of 2. 40 X 107 [0. 00000024] N is equivalent to a force of 5. 40 x 10- [0. 00000005] lb, a force that you would not notice. In fact, it would be difficult to measure such a small force.)Kaz (100 m) 21) I know I can write 60.0 Kaz but I also know I need exponents. I get that 60 x60 = 3.60 x 105 but In my book it shows ( 6.6 7 x 10) (360 x 105) Nm 192x where 15 the other M 2 Ky coming from if boxed 15 written as and also what happened with
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