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. Question 10 0/1 pt 9 3 7 19 0 Details A student was asked to find a 98% confidence interval for the proportion of
. Question 10 0/1 pt 9 3 7 19 0 Details A student was asked to find a 98% confidence interval for the proportion of students who take notes using data from a random sample of size n = 85. Which of the following is a correct interpretation of the interval 0. 13 IZ 0/1 pt '0 3 2:3 19 G) Details A 95% confidence interval for the weight of a small package of M&Ms is (47.82, 48.16) grams. Which of the following statements best describes the confidence level? 0 There is a 95% chance that a randomly selected package will be in the interval. 0 95% of similar intervals will contain the actual mean weight. 0 There is a 95% chance that the mean weight of packages will be in this interval. 0 95% of package weights are in this interval. 0 Question 12 V E 0/2 pts '0 3 8 19 G Details A student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 27. Which of the following is a correct interpretation of the interval 11 IZ 0/1 pt '0 3 8 19 G) Details A sample of 58 Charleston County households have a mean income of $21,216 with a standard deviation of $5,536. Find a 90% confidence interval for the true population mean income for households in Charleston County. Round your answers to the nearest dollar. l IZ 0/1 pt '0 3 3 19 6) Details You intend to estimate a population mean ,u with the following sample. 52 60.1 36.1 13.6 32.1 57.7 31.6 You believe the population is normally distributed. Find the 95% confidence interval. Enter your answer as an open-interval (i.e., with parentheses and separated by a comma) for example (2.45, 3.69). Round to the nearest hundredth (two places after the decimal). Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places
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