. Question 11 0/1 pt 9 3 2 19 0 Details Let f(x) be the rational function graphed below. 18 17+ 16 - 15 O 14 + 13 11 + 10 - 9 - N 14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 -10 -11 - -12 - Q Find the following features of the graph. Vertical asymptote: x Horizontal asymptote: y = Hole at x x-intercept at x = Based on these features, what is the formula for f(a)? f (2) =Question 12 0/1 pt 5 3 2 19 0 Details Let f(x) be the rational function graphed below. -11 -10 -9 -8 -7 -6 -5 -4 -3 2 4 6 7 8 -T -10 Q Find the following features of the graph. If the graph does not have any of the listed features, enter "DNE". Vertical asymptote(s): x = Horizontal asymptote: y= Hole at x = y-intercept at y = Based on these features, what is the formula for f(a)? f(z)Question 13 0/1 pt 3 19 0 Details For each function, determine the horizontal asymptote. x2 + 1 g (a) ha: v Select an answer 203 + 2 no horizontal asymptote h (ac ) = ac' + 1 a horizontal asymptote at y=0 ha x2 + 2 a horizontal asymptote at y=1 2 3 + 1 f (20) = has Select an answer V 202 + 2 Submit QuestionQuestion 13 0/1 pt 9 3 19 0 Details For each function, determine the horizontal asymptote. x2 + 1 g(a) = has Select an answer 203 + 2 ac2 + 1 h (ac ) = ha: V Select an answer x2 + 2 no horizontal asymptote 2 3 +1 a horizontal asymptote at y=0 f (ac) = has ac2 + 2 a horizontal asymptote at y=1 Submit QuestionQuestion 13 0/1 pt 9 3 7 19 0 Details For each function, determine the horizontal asymptote. ac2 + 1 has Select an answer 23 + 2 ac2 + 1 h() = has Select an answer V 2c2 + 2 2 3+ 1 f (ac) = ha: V Select an answer x2 + 2 no horizontal asymptote Submit Question a horizontal asymptote at y=0 a horizontal asymptote at y=1Page No. Date e To find * ( x ) = > As vertical Asymtote is 2= 1 so (-1 ) will be on denominator x intercept at X = - 3 So ( u + 3 ) will be on Numerator Hole at 21 = a means ( 21 - 2 ) will be on Numerator and denominator both so flu) is of the form : 9 ( 2 + 3 ) ( 21 - 2 ) ( 26 - 2 ) ( 21 - 1 ) Now Horizontal Asymtote Y = 3 means 7 120 ) = a (2+ 3 ) ( 2 - 2 ) ( 21-2 ) ( 21 - 1 ) 9 = a ( 0 + 3 1 0/ 2 ) a = - 3 10- 2) ( 0 - 1 ) So * (x ) = - 3 ( x+3) (2 -2) (2 - 2 ) ( x - 1 )Page No. Date 11 Given fix) be a Rational function we need to find a ) vertical Asymtote : 2 = The vertical lines shown in the graph Represent vertical Asymtote. b ) Horizontal Asymtote : y = 3 1 The Horizontal line shows the Horizontal Asymtote ( ) Holes at X = 2 The circle on graph Represent Holes in the graph wort x- intercefat at x = -31 ( NO) ( IS )Date on checking the graph , we seen a ) vertical Asymtote : 2 = 1 1 - 4 The vertical lines Represent the Vertical Asymtote b ) Horizontal Asymtote : y = 0 Holes at 2 = DNE on checking the graph we don't see any notes . ly intercept at y = - 1 1 It is that point where graph cut the y axisDate NOW In order to find #1xc ) . As vertical Asyntote are 2 =1 , - 4 61 + 4) and (1 -1) will be on Denominator = > Vzo is Horizontal Asymtote so Degree of Numerator will be less than degree of denominator so + (X ) will be of form a ( 21 - 1 ) ( x1 + 4 ) Now we have given y intercept at y = - 1 so we find value of 9 with this + ( 21 ) OL ( 21 - 1 ) ( x + 4 ) - 1 a 9 9 = 4 (0 - 1 ) ( 0+ 4 ) Hence 7 ( x ) = 4 (2(- 1) 121+ 4 )