Question 11 The motion diagram above records the motion of a ball launched from ground level. While it is in the air, the only force acting on the ball is the force of gravity. Use 9 = 10 m/s2. Note that the ball has a constant velocity in the xdirection of 10 m/s, and that the dots on the motion diagram are recorded every 1.0 s. Question 113 0 Homework I Answered I Due Oct 3rd, 5:30 PM What is the ball's time of flight? 5 Type your numeric answer and submit You are correct Explanation x With the dots being recorded once every second, we can see that it takes 4 seconds to go up to its maximum height, and 4 more seconds to come back down. That's a total time of8 seconds. Answered -Correct! - 4attempts left {I Resubmit @ Question 11b 0 Homework I Answered I Due 0ct3rd, 5:30 PM What is the ball's maximum height? m Type your numeric answer and submit 30 \\/ You are correct 1" Openi Question 11: O Homework Answered Due Oct 3rd, 5:30 PM What is the vertical component of the ball's initial velocity? m/s Type your numeric answer and submit 40 \\/ You are correct Explanation x One way to find the initial vertical velocity is to use the equation: vy : viy l ayt In this case, Vy is 0 m/s at maximum height, and the acceleration is ay : 10 m/sz, taking positive to be up. This gives an initial vertical velocity of: Viv = th = (10 m/SZ)(4.O s) = 40 m/s Answered Correct! 4 attempts left Question 11d 0 Homework Answered Due Oct 3rd, 5:30 PM What is the launch angle, measured from the horizontal? degrees Type your numeric answer and submit 82.8 \"7| 0P You are incorrect