Question 12 {1 pointl A survey of workers {age 25- or older} in New York State was taken and workers were asked to indicate if they had less than $10.00!) in savings. The 95% confidence interval for the true proportion of workers {age 25+] that have less than 510.000 in savings is: {39902, A5614]. Based on the CI provided above. what is the value of the sample proportion used to build this interval? In other words. what is the point estimate of the true proportion. O 13 = . 42753 Q It cannot be determined. Of} : .02856 Question 13 {1 pointl [Same context as the previous problem] The 95% confidence interval for the true proportion of workers {age 25+] that have less than 510.000 in savings is: {39902. A5614]. Based on the CI, what is the MARGIN 0F ERROR for this interval? 0 It cannot be determined. ()dl C)413 .02856 .42758