QUESTION 16 - Bearingspecification(2 points) In the previous question you calculated a belt load for running and static cases. Given that the shaft length is 1 meter, calculate the reaction forces on the bearing near the pulley (bearing 1) and the bearing at the far end of the shaft (bearing 2). For this question you will upload a hand-drawn solution, including free-body diagrams and calculations, for the reaction forces for bearings 1&2 for the static and running cases. Some hints: 1. This solution will require you to draw known forces and find unknown reactions in 2 perpendicular planes and then add the horizontal and vertical reaction forces as vectors to find the reaction force (hypotenuse). 2. Bearings are usually mounted as near as possible to the ends of the shaft without fouling the other machine elements. The bearing at the far shaft end can be mounted at the 1 meter point. The bearing at the pulley end should allow clearance to assemble the pulley. 3. Bearing reaction forces are typically simplified as a single point load through the bearing centre. QUESTION 17 - Bearingspecification(2 points) We will simplify our design by using the same bearing for both bearings at either end of the main shaft. This approach is quite common as it is much easier to implement and costs less to buy two bearings of the same type, rather than two specific bearings. It also helps the engineer to sleep well at night as they don't have to worry about whether the bearings are assembled the right way around. But using the same bearing type for both ends of the main shaft means that we must design for the bearing that sees the greatest load (we will call this the worst case loaded bearing). State the Static Load [stat_load] and Dynamic [dyn_load] that you have calculated for the worst case loaded bearing. If we require an L10 design life or 7,000,000 cycles using a rolling element bearing (k = 3.0), state the Static Load Rating [static_load_rating] and Dynamic Load Rating [dyn_load_rating] required for the worst case loaded bearing.