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QUESTION 18 The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak
QUESTION 18
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tailed test of the mean for the stressed oak furniture is 650. The calculated value of Z test statistic is a positive number that leads to p-value of 0.08 for the test.Suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650. What would be p-value of the one-tailed test?
| A. | 0.84 | |
| B. | 0.04 | |
| C. | 0.19 | |
| D. | 0.96 |
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