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Question 19 What is the rate law for the following mechanism: A+B+CD (slow, rate ki) A+D 2E (fast equilibrium; rate of forward reaction: k, rate

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Question 19 What is the rate law for the following mechanism: A+B+CD (slow, rate ki) A+D 2E (fast equilibrium; rate of forward reaction: k, rate of reverse reaction: k) E+G =H (fast equilibrium; rate of forward reaction: kz, rate of reverse reaction: k-3) O A Rate= kz (kyk_1) [A][B][C] o 8 Rate= k2 (A)?[B][C] Rate-k1 [A][B][C] Rate=k2 [A][D] OD Rate- (kj/k_1) [A][B][C] OE

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