Question 2 1 pts Denote the population at time t by y(t). Log-log plot of the data means plotting log1, t vs. log1. y(t). The equation of a straight line with slope -2.3 is Y = -2.3X + b. Since the log-log plot results in such a line, y(t) must satisfy O y(t) = -2.310g10 t + b O log10 y(t) = -2.3t + b log10 y(t) = -2.3 10g10 t + log10 b O y(t) = -2.3t + b O log10 y(t) = -2.310g10 t + b Question 3 1 pts Solving the equation for y(t) gives Oy(t) = 10-2.3t 106 Oy(t) = t-23106 O y(t ) =-+2.310b Oy( t) = bt-2.3 O y(t) = -t-2.3610Question 4 1 pts Finally, in order to nd 6 we use the fact that the population size at time 1 was 300. Since we denoted the population at time t by y(t), the equation is y(1) = 300. We plug in t = 1 in our answer to the previous question and solve the equation for b: o b =1n(300) 0 b 2 10300 o b = 300 05:30