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Question 2: [36 marks] = An average operating data for conventional activated sludge treatment plant as follows: Wastewater flow = 35000 m/d. Hydraulic residence time
Question 2: [36 marks] = An average operating data for conventional activated sludge treatment plant as follows: Wastewater flow = 35000 m/d. Hydraulic residence time = 0.311 d. Influent biological oxygen demand (BOD) = 250 mg/L. Effluent biological oxygen demand (BOD) = 20 mg/L. Mixed liquor suspended solids (MLSS) = 2500 mg/L. Effluent suspended solids concentration from the bottom of clarifier = 9700 mg/L. Effluent overflow suspended solids concentration from clarifier = 30 mg/L. Quantity of waste sludge = 220 m/d. Based on the information above, determine the: a) volume of aerated basin in m, [5 marks] b) food to microorganism ratio in kg BOD/d. kg MLSS, [5 marks] c) efficiency of BOD removal in %, [5 marks] d) sludge age in d, [5 marks] e) recycle flow in md and [8 marks] f) rate of generation of microorganism inside the aerated basin in kg/d. [8 marks]
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