Question 2

A Material Review Board is being formed to review discrepant material. The Engineering Manager will chair the board. 3 engineers will be selected out of 9 available to also be on the board. How many different ways (combinations) can these engineers be selected?

Group of answer choices

120

126

504

84

28

Question 3

For the classic binomial problem, which of the following is not true?

Group of answer choices

The success/failure probabilities are the same for each trial.

Theoretically, the total possible number of trials is infinite.

There is not a sample size per se, but a number of trials of the experiment.

The heads/tails distribution when flipping a coin illustrates the classic binomial

None of the above. (All are the above are true.)

Question 4

1000 parts are produced in a batch on a machine of which 15% in the batch (150 parts) are known to be defective. A sample of 25 parts is taken from the batch. To get the probabilities of getting a given number of defective units in the sample, which distribution should be used?

Group of answer choices

Poisson because I can count the defective units that are there, but not count the ones that are not there.

Hypergeometric because I have a small finite population from which the sample is drawn and the probability of being defective are constant with each part inspected.

Binomial because I have a constant defective rate and parts can be either defective or not defective.

Binomial estimation of hypergeometric because the change in the probability of being defective is very small as each part is taken from the sample for inspection.

Question 5

100 parts are presented for inspection. The known defective rate of the process which produced the part is 2%. To analyze the distribution of numbers of defects possible in the sample I would use

Group of answer choices

Poisson because I can count the defective units that are there, but not count the ones that are not there.

Binomial because I have a constant defective rate and parts can be either defective or not defective.

Hypergeometric because I have a small sample size and the probability of being defective will change with each part inspected.

Binomial estimation of hypergeometric because the change in the probability of being defective is very small as each part is taken from the sample for inspection.