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.Question 20 G 0/1 pt 9 100 = 4 0 Details The mean daily production of a herd of cows is assumed to be normally

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.Question 20 G 0/1 pt 9 100 = 4 0 Details The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 32 liters, and standard deviation of 6.9 liters. A) What is the probability that daily production is less than 37.7 liters? Use technology (not tables) to get your probability. Answer= (Round your answer to 4 decimal places.) B) What is the probability that daily production is more than 16.3 liters? Use technology (not tables) to get your probability. Answer= (Round your answer to 4 decimal places.) Warning: Do not use the Z Normal Tables... they may not be accurate enough since WAMAP may look for more accuracy than comes from the table. Question Help: Message instructor Submit Question Question 21 0/1 pt 9 100 2 4 0 Details Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with a mean of 130.7 ft and a standard deviation of 4.6 ft. A tree of this type grows in my backyard, and it stands 121.5 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter. P(X 137.1) = Enter your answers as decimals accurate to 4 decimal places. Question Help: Message instructor Submit Question Question 22 0/1 pt 9 100 = 4 @ Details In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally distributed with a mean of 56 inches, and standard deviation of 7.2 inches. A) What is the probability that a randomly chosen child has a height of less than 55.4 inches? Answer= (Round your answer to 3 decimal places.) B) What is the probability that a randomly chosen child has a height of more than 41.5 inches? Answer= (Round your answer to 3 decimal places.)

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