Question 24 (3 points) Kinematics Javg = Ad = 4-d davg = = - dj-di tf-ti 1.1 Ad=At 1.4 ... 1.2 vj = vi + t 1.5 = agravity 9.8 m/s ... 1.3 vj = v+2aAt .1.6 Ad=vAt+ ... 1.7 = - 1.8 Dynamics Fnet = ma ... 2.1 == Uniform Circular Motion ac = v .. 3.1 v = 2 ... 3.2 T F = mg ... 2.2 Ff=f FN ... 2.3 a = 4r f ... 3.3 ac = 4x+ .. 3.5 = mac 3.4 ... Fe= mv2 ... 3.6 r A Firefighter drags a hose of mass 27 kg along a horizontal platform at a constant speed of 1.8 m/s by applying a force of 1.12 x 102 N [27 above the horizontal]. What is the coefficient of kinetic friction between the hose and the platform? (1) Indicate the equation number of the equation/s you used and (2) the coefficient of kinetic friction.