Question 25 (3 points) The Wave Nature of Light c = 3.00 x 108m ... 1.1 v = fx ... 1.12 f = + ... 1.21 Ain2 = 12 n = 12 n1 n1 sin 01 = n2 sin 02 ... 1.3 ... 1.13 sin 0 = n2 n1 ... 1.22 |PnS1 - PnS2) = (n -2) > ...1.14 sin On = (n- )x ... 1.23 sin On = In In = (n-3 ) ... 1.15 sin Om = ma ... 1.24 sin On = (n-3)x ... 1.31 Im = mLX ... 1.16 (n-2 )LX ... 1.25 Ax = LX 2t = (m+ ; ) > ... 1.32 nfilm ... 1.17 2t = na n film ... 1.26 Ax = L () sin Am = (m+2 )x ... 1.33 W ... 1.18 sin Om = n w ... 1.27 ym = (m+ 2 )LX yn = nLx ... 1.34 ... 1.19 Ay = LA ... 1.28 d = N ... 1.35 Light shines through a single slit whose width is 5.6 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m away. The distance between the middle of the central bright fringe and the first dark fringe is 3.5 mm. What is the wavelength of the light? (1) Indicate the equation number of the equation/s you used, (2) the wavelength of the light