Question 2.5.1. how did we get 74.2% as the required probability?

Probability of a chosen student to be a male = 29/62

the probability that the chosen student has full time employment = 1/3

probability of the student chosen to be a male and having fulltime job = 7/62

P(A or B) = P(A) + P(B) - P(A intersection B).

I am not getting the same answer.