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Question 26 T = 5 sin (100() satisfies. 2 T = 5sin(1 sausn 26. Let QI be a constant so that f'/(c) = --js for
Question 26
T = 5sin"(1 sausn 26. Let QI be a constant so that f'/(c) = --js for the second derivative f" (c) of Let Q = In(3 + IQII). Then T = 5sin2(100Q) satisfies (A) O T < 1. 2 7+20z = + 17C2 + + 9. 27. Let = QI be the point of inflection of f (c)
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