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QUESTION 27 You run an Anderson-Darling normality test in MINITAB. The output graph of this test of normality has an associated P value of

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QUESTION 27 You run an Anderson-Darling normality test in MINITAB. The output graph of this test of normality has an associated P value of 0.678 (P=0.678). How would you interpret this result? The null hypothesis for a normality test assumes that the data are not normally distributed. The P value in the graph indicates that you should accept the null hypothesis. So you would conclude that the data are not normally distributed. The null hypothesis for a normality test assumes that the data are not normally distributed. The P value in the graph indicates that you should reject the null hypothesis. So you would conclude that the data are normally distributed. The null hypothesis for a normality test assumes that the data are normally distributed. The P value in the graph indicates that you should accept the null hypothesis. So you would conclude that the data are normally distributed. The null hypothesis for a normality test assumes that the data are normally distributed. The P value in the graph indicates that you should reject the null hypothesis. So you would conclude that the data are not normally distributed. It is not possible to conclude whether the data are or are not normally distributed from this probability (P) value.

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