QUESTION 3: [20 marks] Below figure shows a part of the production line of raspberry juice in F&B company. Initially, the production begins with the screw pressing of raspberies and topping of water to form the diluted raspberry juice (p = 1030 kg/m). The diluted raspberry juice is then split into three different streams (stream 2, 3, 4) to be stored in 3 different storage tanks. It is known that the gauge pressure inside the storage tank for raspberry juice is 63.78 kPa. Case 1 V - ? D 11.39 m/s 1.33 m V 0.29 V, V4-8.39 m/s D-? V -0.31 V2 - ? Dz - 0.78 m Pc-? 7 V = ? V-7 Dy 0.31D + 0.57D4 3.89 m P-72.61 m ? 2-7 Pgauge = 63.78 kPa P,=? Case 2 Pa=7 7 (a) Compute the volumetric flow rates (V, V2, V3, and V), diameters (D, and D), and velocity (v and v). [8 marks] (a) Compute the volumetric flow rates (V, V2, V3, and 4), diameters (D, and D), and velocity (V and v3). [8 marks] (b) Calculate the hydrostatic pressure (gauge) at points 5, 7, and 8. [4 marks] (c) If the pipe of the stream 3 rupture at the point 5, determine the maximum height that the raspberry juice can shoot up to. Make assumptions/analysis to simplify the calculation. [Hint: Use point 5 and 6 as the system] [4 marks] (d) If the old storage tank has a rupture point (with very large diameter hole) at the point 8, compute the discharge velocity of the raspberry juice as it leaves from point 8. Utilize some assumptions/analysis to ease the calculation. [Hint: Use point 8 and 9 as the system] [4 marks]