Question 3 (8 marks): Taylor series of sin(x) is highlighted below. sin x = (1)"x2n+1 (2n + 1)! n=0 Build a code in MATLAB using "while" loop and find the approximate value of sin (x) at x: right after the error between the actual value and approximate Taylor value of sin(x) at x = smaller than 0.5%. 2 725 At what "n" the error gets smaller than 0.5% for the first time? What is the exact corresponding error value in percentage in the obtained "n"?