Question 3 In Professor Friedman's economics course the correlation between the students' total Not yet scores before the final examination and their final-examination scores is answered P = 0.55 Marked out of 1.00 The pre-exam totals for all students in the course have mean 270 and standard deviation 30. The final exam scores have mean 70 and standard deviation 9. Professor Friedman has lost Julie's final exam but knows Flag that her total before the exam was 310. Pre-exam totals and final exam scores have a bivariate question normal distribution. Professor Friedman decides to give her as a final exam grade the value of the conditional expectation of final exam scores for students in the class that had a total of 310 before the exam. If he does that, what will be Julie's final exam score? Select one: O a. 76.60 O b. 60.06 O c. 49.3 O d. 89.2Question 16 Not yet answered Marked out of 2.00 '7 Flag question This is a good exercise to practice calculating joint probabilities and covariance or calculating independence, to show understand of what independence and correlation means. In life we usually express ourselves in words. We use tables and formulas to model mathematically the problem in order to find an answer to our questions. Review Lecture 20, 21, 22 and Chapter 6 in the book if you are having trouble understanding this question. Exercise. Two species, A and B, affected by the same environmental factors, are being studied to see if there is association between them. The species live in fruits. The random variable X measures the number of species A fruit, and the random variable Y measures the number of species B per fruit. The joint probability mass function PtX,Y) is given by the following table. X\\v 0 1 2 0 0.40 0.1 0.1 1 0.1 0.1 0.02 2 0.1 0.02 0.03 3 0.01 0.01 0.01 The probability that the number of species B is larger than the number of species A in a fruit is We can say doubt the Choose... without J Choose... the number of species A is (albeit very slightly) related to the number of species B in the flower found by adding the probability of the event {(0,1), (0,2),(1,2)} where the first number in a pair is the number of species A and the second number