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Question 3 Not yet answered Marked out of 10.30 'E' Flag question Time left 1139131 (NOTE: IN ORDER TO GET FULL MARKS, SHOW ALL CALCULATIONS
Question 3 Not yet answered Marked out of 10.30 'E' Flag question Time left 1139131 (NOTE: IN ORDER TO GET FULL MARKS, SHOW ALL CALCULATIONS AND STEPS. FAILURE TO DO SO WILL RESULT IN A SCORE OF "0".) A Psychology professor is teaching sections A and C of Psychl. The professor knows from the past that the student exam marks of section A follows a normal distribution with an average of 62. and a variance of 64, while the student's exam marks of section C follows a normal distribution with an average of 72, and a variance of 400. 1. Find the probability that the average exam marks by a random sample of 90 students in section C is greater than 65. 2. What is the probability that the average exam marks of 10 randomly selected students from section A is one mark higher than the average exam marks of 15 randomly selected students from section C? 3. The professor declares that no more than 3 out of 10, of section C's students, will get the average mark. What is the probability that in a random sample of 80 section C students, 22 or more will get the average mark? 4. (Solve this part independently}. A random sample of 8 Adanac bank employees was taken to help estimate the average amount of timetx) employees spent per week on their cell phones. The sample data and some relevant infm'mation are listed below: 15. 5, 8,11, 7,12, 2.14. Find an unbiased estimator of the aVerage time per week for all bank employees
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