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Question 4 > 0/1 pt 3 99 Detail For a normal variable X ~N(u= 74.6, = 17.12), find 20.28, the value that divides the

Question 4 > 0/1 pt 3 99 Detail For a normal variable X ~N(u= 74.6, = 17.12), find 20.28, the value that divides the area under the density curve into 0.72 to the left and 0.28 to the right. 0.28= (Round the answer to 2 decimal places) Question Help Video 1 Video 2 Video2 Written Example 1 Message instructor Post to forum.

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