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Question 4 0/5 pts 9 10 2 4 @ Details You are interested in finding a 95% confidence interval for the average number of days

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Question 4 0/5 pts 9 10 2 4 @ Details You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 10 randomly selected college students. Round answers to 3 decimal places where possible. 0 0 0 0 3 0 0 2 9 5 a. To compute the confidence interval use a (? V ) distribution. b. With 95% confidence the population mean number of days of class that college students miss is between and |days . c. If many groups of 10 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days. Question Help: Message instructor Submit Question Question 5 0/2 pts 9 10 4 0 Details Assume that a sample is used to estimate a population mean /4. Find the 8% confidence interval for a sample of size 4 with a mean of 17.1 and a standard deviation of 10.8. Enter your answer as a tri-linear Inequality accurate to 3 decimal places. Question Help: Message instructor Submit Question Question 6 0/2 pts 9 10 - 4 0 Details Lian wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 41 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 11.1 and a standard deviation of 2.6. What is the 98% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Assume the data is from a normally distributed population. Round answers to 3 decimal places where possible. Question Help: Message instructor Submit

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