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Question 4 (1 point) Point P lies between two point charges, q1 = (3.5940x10^0) C and q2 = (4.9060x10^0) HC respectively. Point P is at

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Question 4 (1 point) Point P lies between two point charges, q1 = (3.5940x10^0) C and q2 = (4.9060x10^0) HC respectively. Point P is at a distance R1 = (2.45x10^0) cm from charge 1, and R2 = (4.702x10^0) cm from charge 2. Calculate the net electric field at Point P in N/C. You do not need to enter a unit vector in your answer, but a negative sign is needed if the electric field points along the negative x-axis. +X 91 r1 92 P Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10

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