Question $4(2$ points$)$

The derivative of $g(x)=(2x^4-3x{)}^5$ is:

$g^{\text{'}}(x)=(8x^3-3)(10x^4-15x{)}^4$

$g^{\text{'}}(x)=5(8x^3-3{)}^4$

$g^{\text{'}}(x)=(40x^3-15)(2x^4-3x{)}^4$

$g^{\text{'}}(x)=(8x^3-3{)}^5$