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QUESTION 4 c) A parachutist bails out of an aeroplane and is in free fall for a time of 4 seconds as shown in
QUESTION 4 c) A parachutist bails out of an aeroplane and is in free fall for a time of 4 seconds as shown in the diagram below. At a point, the parachute opens and thereafter, the parachutist reaches the ground with a speed of 3 m s. If the total distance of the fall is 950m. What is the deceleration rate after open the parachute (acceleration is constant after open the parachute) ? Note: acceleration due to gravity, g = 9.8 m s-2 v=v + at v = v + 2a (x-xo) 1 = at + vot + xo x = Vo=0 m s_ Free Fall t=4s (a) (b)
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Answer Velocity after 4 seconds is vv gt 0980 ms 40 s 392 ms ...Get Instant Access to Expert-Tailored Solutions
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Fundamentals of Physics
Authors: Jearl Walker, Halliday Resnick
8th Extended edition
471758019, 978-0471758013
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