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QUESTION 4 Given the following polynomial, p (x) =7x' - 10x2+8x-5 1,5 According to the rational zero theorem, the possible zeros for p(x) are 1,7

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QUESTION 4 Given the following polynomial, p (x) =7x' - 10x2+8x-5 1,5 According to the rational zero theorem, the possible zeros for p(x) are 1,7 It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form given below. Find the values for a,b, p (x) = (x - 1)(ax

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