Question 5 of 8 1.67 / 15 Now, suppose you displace the cart 0.2 m to the left of equilibrium as shown below. A 0.9 kg cart is attached between two horizontal springs, of stiffness 2 N/m, which are attached at each en track. The cart has low-friction wheels, so friction is negligible. The relaxed length of each spring is 0.1 m. x=0.3 m X=0 What is the net force by the springs on the cart now? x=0.5 m x=1.0 Fnet = ( 1 i Save for Later Part 1 Attempts: 0 of 4 used Subm Your answer is partially correct. Part 4 What is the force by the left spring on the cart? F = ( i 0.8 If you release the cart from rest (when it is displaced to the left of equilibrium as shown above), its position 0.1 s later? (Use the approximation U avg ~ P future / m.) Hint " (1 = 0.1s) =1 1 Save for Later i ) m Attempts: 1 of 4 used Submit Ans Save for Later Part 2 Attempts: 0 of 4 used Subm What is the force by the right spring on the cart? Part 5 F = ( i Save for Later 12:25 PM Sat Sep 30 ... 83% education.wiley.com Chapter 2: Homework 2 Question 5 of 8 1.67 / 15 Save for Later Attempts: 0 of 4 used Submit Answer Part 5 Now, att = 0.1 s, what is the net force by the springs on the cart? Fnet (1 = 0.1 s) = ( i Save for Later Attempts: 0 of 4 used Submit Answer Part 6 What will be the position of the cart 0.1 s later, att = 0.2s after being released? 7 (1 = 0.25) = ( i i i ) m eTextbook and Media Save for Later