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Question 5 We wish to compute 20 2 + 2 13 73 + 472 - 162-64 da . 1 point How Did I Do? (i)
Question 5 We wish to compute 20 2 + 2 13 73 + 472 - 162-64 da . 1 point How Did I Do? (i) We begin by factoring the denominator of the rational function. We get 23+ 4x - 16x - 64 = (x - a) (2 -6)2 for a # b . What are a and b ? FORMATTING: Make sure b corresponds to the factor of the denominator that repeats twice. a = Number b = Number (ii) Next, we express the fraction in the form 202 + 2 A B C 23 +4x2 -16x - 64 - a (2 - 6)2 Give the exact values of A , B and C . FORMATTING: Make sure A, B, and C correspond to the appropriate denominators, as given in the above setup. A = B = C = (ii) Finally, we use this partial fraction decomposition to compute the integral. Give its approximate value with 3 decimal places. 2 2 + 2 -3 23 + 4x2 - 16x - 64 da ~ Number Hint Penalty Warning 0.0 View HintQuestion 4 We wish to compute -2 + 5 da . 1 point 23 + 7x2 +12x How Did I Do? (i) We begin by factoring the denominator of the rational function to obtain: 2 3 + 7x2 + 1220 = 20 ( 20 + a) (20 + 6) for a
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