Question 55 Adult IQs are normally distributed with a standard deviation of 15. We sample 10 adults and find an average of 95. Construct a 95% confidence interval on the mean adult 10 Marked out of a (05.513, 104.407) Question 34 b. (03.967 106.033) (85.703, 104.297) Od. (65.6, 124.4) Clear my choice Time left 1:46:32 To study the effect of soothing music on a person's blood pressure, two random samples of 220 adults were drawn One sample (sample 1) Istened to soothing music for 5 minutes prior to having their blood pressure taken, while the other sample tample 21 sat in silence from previous studies, it was found that both populations have a standard deviation of 39 18. The average systolic blood pressure from the music sample was 114.5. The average systolic blood pressure from the silent sample was 122.0. Construct a 90% confidence interval on the difference in population mean blood pressures (music silent). a (13.6219, 0.9701) b. (14.4443, 2.1992) Dc (-16.9903, 0.3903 Clear my choice Question 35 I'm here to ask the tough questions like "can you get a haircut so good it makes you better at Mario Kart? 4 volunteers in need of a free trim ran a time trial on a randomly selected track and reported their times in seconds both before and after their haircuts. This is summanzed in the table below. Mario Kart ABCD Before the haircut 10294 82111 After the haircut 101930211 Is there evidence at the a-0.05 level of significance that there is any difference in Mario Kart speed based on your haircut? INFERENCE QUESTION REMINDER: For confidence intervals, your answer will be the lower bound (i.e. minus the margin of error). for hypothesis tests, your test statistic. These should be reported with two (2) figures after the decimal. For sample size determinations, report the sample size. This should be reported as a whole number. Arswer A manufacturer of mosquito repellent claims that the average amount of time their repellent is effective is at least 3.5 hours. A consumer group tests the claim using five randomly selected people if the average time of effectiveness from the sample was 18 hours with a standard deviation of 0.76 hours, what is the critical value (CV) test statistic (TS), and decision for this test? (Use a = 0.025) 04 CV-2776 TS -0.88, fail to reject HO b. CV = 2.776 TS = 0.88, fail to reject HO CCV-2.571, TS =-0.39, fail to reject HO Od. CV-2.571. TS = -0.88, fail to reject HO UC CV-2571, TS = 0.39, fail to reject HO