Refer to the memory snippet and the following registers values to answer the next 4 questions. SS = 483A, DS-4871, DI-52A4 BP=160B,, SP-261E,, Physical address () Content () 92 4D9C7 CD 8A 4F 14 84 29 4D9CO F9 B1 4C 4D9BD A5 B7 16 41 4D9B9 8E 6A D5 59 5B 4D9B4 DO 5B 4D9B4 DO 1- What will be the value of SP and BX after executing the following two instruction: POP BX POP BX The final value of SP (in hexadecimal) = 261E The final value of BX (in hexadecimal) = B14C * write the values without any additional character 2- What will be the value of CX after executing the following instruction: MOV CX, [DI]+0005 The final value of CX (in hexadecimal) = * write the value without any additional character 3- What will be the value of BP, source operand and destinaation operand after executing the following instruction: XCHG (BP] + 100A, DI The final value of BP (in hexadecimal) = The final value of source operand (in hexadecimal) = The final value of destination operand (in hexadecimal) = * write the value without any additional character 3- What will be the value of BP, source operand and destinaation operand after executing the following instruction: XCHG (BP] + 100A, DI The final value of BP (in hexadecimal) = The final value of source operand (in hexadecimal) = The final value of destination operand (in hexadecimal) = * write the value without any additional character 4- Consider the following two instructions: MOV SP,0261AH PUSH DX After executing the above two instructions a- The value stored in memory will be replaced by D b- The value stored in memory will be replaced by D * write the values without any additional character Please answer all parts of the question.