Question 6 Go/1 pt 05 9 0 Details The point (-14, 5) lies on a differentiable function f(x). The tangent line to f(x) at I = -14 also goes through the point ( 9, 0). What is f'(-14) ? f'(-14) = Question Help: Message instructor Submit Question Jump to Answer Question 7 6 0/1 pt 95 9 0 Details Use the limit definition of the derivative to find the slope of the tangent line to the curve f(r) - 2x2 at c - 3 Evaluate each of the following and enter your answers in simplest form: Step 1 f (3 + h) = Step 2 f (3 + h) - f(3) = Step 3 f(3 + h) - f(3) h Step 4 lim f(3 + h) - f(3) h So, f'(3) Question Help: Message instructor Submit Question Jump to