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Question 6 Not yet answered Marked out of 1 If the value of the equilibrium constant, K, for the reaction below: 2502 (9) + 02

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Question 6 Not yet answered Marked out of 1 If the value of the equilibrium constant, K, for the reaction below: 2502 (9) + 02 (9) = 2503 (9) is 4.36. Accordingly, what is the value of the equilibrium constant for the following reaction? SO; (g) = 1/202(g) + 50, (g) P Flag question Select one: 2.95 O 0.479 0.229 02.09

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