Question 7 5 pts Now we add a plexiglass atmosphere above the ground (as in class). The set-up of this environment has the following properties: 1. The atmosphere is completely transparent to the incoming solar radiation (it does not absorb any solar radiation) 2. The atmosphere's temperature is T and it emits IR radiation according to the Stefan-Boltzmann law both upward and downward, by the same amount 3. The atmosphere completely absorbs the IR radiation coming from the ground 4. The ground temperature is Tg and the ground emits IR radiation according to the Stefan Boltzmann law 5. The ground completely absorbs all radiation it receives At the top of the atmosphere, solar radiation F (the same value as Q6) goes down, while an upward IR radiation, originated from the atmosphere, goes out to space. From the energy balance at the top of the atmosphere, determine Ta in (K). Edit View Insert Format Tools Table 12pt Paragraph (6378)21360 (10.3)=4(6378) (5.67 108) T 1360 0.07 = 4(5.67 108) T . 238 = (5.67 108) T Ta = 254.5356 Now we change the properties of the atmosphere from Q7 to account for a variable opaqueness of the atmosphere to IR. The statements (1), (4), (5) in Q7 remain the same, but (2) and (3) are modified as (2) The atmosphere's temperature is T and it emits radiation ET both upward and downward ( 01) (3)' The atmosphere absorbs & times the IR radiation coming from the ground. (1 - ) of the IR radiation coming from the ground escapes to space Working out the energy balance at the top of the atmosphere and at the ground, find the expression of To in terms of F, , but not Ta. g