Question 8 2 pts Click Reset and turn off \"Electric field", Place 4 red positive charg e scale at bottom right comer of the simulation window). Place the yellow sensor at a distance of 1.5 m from the red positive charges, on the same horizontal grid line. The red positive charges are each +1 nC, and the yellow positive test charge is a proton [check the charge of a proton in your textback]. Calculate the magnitude of the net electric force on the test charge one on top of each other) on the left side of the simulation window at the intersection of two major grid lines. The grid scale is 1 m = 2 big grid square: 266x 107N 24 %10 N 1621077 W 64Ax 107N Question 2pts Find the magnitude of the electrostatic field at the position of the yellow test charge 16 N/C 24N 22N/C Question 2 pts Click Reset, turn on Grid, and turn off Electric Field. Place a red positive charge on the left side of the simulation window at the intersection of two major grid lin Find the net electric fiekd along the line betwesn the twa charges, 1.5 m to the right of the red positive charge. s. Place two blue negative charges (on top of each other), 2.5 m to the right of the positive charge, along the same horizontal grid line 8N/C 14N/C 22N/C ON/C Question 2 pts What is the direction of the net electric field at this position? to the right no direction, the net electric field is zero. to the left Question 12 2 pts Find the net electric force applied to a positive test charge placed at the position where you calculated the electric field (in the previous question). O 35.2 x 10 19 N 22.4 x 10 19 N O 12.8 x 10 19 N O ON Question 13 2 pts Find the net electric field 0.5 m to the right of the blue charges (along the same horizontal line). O 71 N/C O 72 N/C O ON/C O 73 N/C Question 14 2 pts What is the direction of the net electric field at this position? O to the left O no direction, the net electric field is zero. O to the right Question 15 2 pts Where (along the line connecting the red and blue charges) can a yellow positive test charge be placed such that it is in equilibrium? O half way between the red and blue charges. O to the left of the red charge O one third the way between the charges, closer to the red charge O to the right of the blue charge